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A mass-spring system oscillates with an amplitude of 9.4 cm. If the force constant of the spring of 424 N/m and the mass is 0.69 kg, what is the magnitude of the maximum acceleration of the mass in m/s2?

Respuesta :

MathPhys

Answer:

58 m/s²

Explanation:

According to Newton's second law of motion, the net force on an object is equal to its mass times its acceleration. Thus the maximum acceleration occurs at the maximum force. According to Hooke's law, the force of a spring is equal to the spring constant times the displacement.

F = ma

kx = ma

(424 N/m) (0.094 m) = (0.69 kg) a

a = 58 m/s²

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