jeremiah147
contestada

PARENTING AND CHILD DEVELOPMENT A INSTRUCTOR MANUAL 2. The mother and father both carry a gene for sickle cell anemia, a disease caused by having two recessive genes. They do not have the disease but may pass it on to their children. Complete the grid to determine the chances of having a child born with the disease. Father n Mother r = a gene that carries the recessive trait for sickle cell anemia n = a normal gene without the sickle cell trait A. There is a in chance that any child will have sickle cell anemia and carry two genes for it. B. There is a in chance that any child will carry a gene for sickle cell anemia but not have the disease. C. There is a _ in anemia nor carry a gene for it. chance that no child will have sickle cell​

PARENTING AND CHILD DEVELOPMENT A INSTRUCTOR MANUAL 2 The mother and father both carry a gene for sickle cell anemia a disease caused by having two recessive ge class=

Respuesta :

CypressSage

Answer:

A. There is a 1 in 4 chance that any child will have sickle cell anemia and carry two genes for it. (1/4 or 25%)

B. There is a 2 in 4 chance that any child will carry a gene for sickle cell anemia but not have the disease. (2/4 or 50%)

C. There is a 1 in 4 chance that no child will have sickle cell anemia nor carry a gene for it. (1/4 or 25%)

Explanation:

To determine the chances of having a child with sickle cell anemia, we can use a Punnett square to analyze the possible gene combinations from the parents' genotypes.

Given:

Father (n) × Mother (r)

Possible gametes:

Father: n

Mother: r

Punnett square:

    |     n      |     n     |

----------------------------

r   |     nr     |     nr    |

----------------------------

r   |     nr     |     nr    |

From the Punnett square, we can see that:

  • There are 4 possible combinations for the offspring.
  • Out of these combinations, 1 results in the child having two genes for sickle cell anemia (nn).
  • 2 combinations result in the child being a carrier (nr).
  • 1 combination results in the child being normal (rr).

So, to answer the questions:

A. There is a 1 in 4 chance that any child will have sickle cell anemia and carry two genes for it. (1/4 or 25%)

B. There is a 2 in 4 chance that any child will carry a gene for sickle cell anemia but not have the disease. (2/4 or 50%)

C. There is a 1 in 4 chance that no child will have sickle cell anemia nor carry a gene for it. (1/4 or 25%)


Hope this helps!

Otras preguntas