6. In an insulated vessel, 250 g of ice at 0°C is added to 600 g of water at 18°C. How much
ice remains when the system reaches equilibrium? Assume the heat of fusion of ice is
79.7 cal/g and its specific heat is 0.5 cal/g°C. The heat of vaporization of water is 540
cal/g and its specific heat is 1 cal/g°C.

Respuesta :

To find out how much ice remains when the system reaches equilibrium, we need to calculate the total heat gained and lost during the process. Here's a step-by-step approach to solve the problem: 1. Calculate the heat lost by the ice to reach 0°C: Heat lost = mass of ice * heat of fusion Heat lost = 250 g * 79.7 cal/g Heat lost = 19925 cal 2. Calculate the heat gained by the ice from 0°C to the final temperature: Heat gained = mass of ice * specific heat * temperature change Heat gained = 250 g * 0.5 cal/g°C * 18°C Heat gained = 2250 cal 3. Calculate the heat gained by the water to reach equilibrium: Heat gained = mass of water * specific heat * temperature change Heat gained = 600 g * 1 cal/g°C * (0°C - 18°C) Heat gained = -10800 cal (negative sign indicates heat loss) 4. Total heat gained = Heat gained by ice (2250 cal) + Heat gained by water (-10800 cal) Total heat gained = -8550 cal 5. Since the system is insulated, the total heat lost by the ice is equal to the total heat gained by the system: Total heat lost = Heat lost by ice (19925 cal) + Total heat gained (-8550 cal) Total heat lost = 11375 cal 6. Determine how much ice remains by converting the total heat lost to mass of ice: Mass of ice remaining = Total heat lost / Heat of fusion Mass of ice remaining = 11375 cal / 79.7 cal/g Mass of ice remaining ≈ 142.6 g Therefore, approximately 142.6 g of ice remains when the system reaches equilibrium.