To identify the amount of chloride ions present in 0.1 mol of MgCl2, first know the amount of mols of Chloride. The answer is 0.2 mol since you just need to multiply 0.1 to 2 because there are 2 chloride in the compound. Then, multiply the mols to 6.02x10^23. The answer would be 1.204x10^23 chloride ions.
Answer : The number of chloride ions present in 0.100 mole of [tex]MgCl_2[/tex] are, [tex]1.2044\times 10^{23}[/tex]
Explanation : Given,
Moles of [tex]MgCl_2[/tex] = 0.100 mole
As we know that, 1 mole contains [tex]6.022\times 10^{23}[/tex] number of ions.
In [tex]MgCl_2[/tex], there are one magnesium ion and two chloride ions.
As, 1 mole [tex]MgCl_2[/tex] contains [tex]2\times (6.022\times 10^{23})[/tex] number of chloride ions.
So, 0.100 mole [tex]MgCl_2[/tex] contains [tex]0.100\times 2\times (6.022\times 10^{23})=1.2044\times 10^{23}[/tex] number of chloride ions.
Therefore, the number of chloride ions present in 0.100 mole of [tex]MgCl_2[/tex] are, [tex]1.2044\times 10^{23}[/tex]
