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A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0.8 seconds when caught. If the softball has a mass of 0.2 kilograms, what’s the force of the impact? Use F = ma, where .

Respuesta :

Answer:  The force of the impact is 8.0 Newtons

Explanation:

Given

[tex]Initial\: velocity(V_i)= 32.0\, \frac{m}{s} ,Final\, velocity ( V_f)=0 \frac{m}{s},Time(t)=0.8 seconds[/tex]

Using equation of motion

[tex]V_f=V_i+at[/tex]  where a= acceleration of softball

=>[tex]0=32+a\times 0.8=>a= -40\, \frac{m}{s^{2}}[/tex]

Thus magnitude of the force of the impact is

[tex]F=\left | ma \right |=>F=0.2\times 40\; Newtons=8.0\: Newtons[/tex]

Thus the force of the impact is 8.0 Newtons

Answer:

8 Newtons.

Explanation: