Respuesta :
Answer:
Option C is correct.
Step-by-step explanation:
Given Equation:
[tex]\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}[/tex]
To find: Solution of the Equation.
Consider,
[tex]5(b^3-2)=2(3b^3-2b^2-5)[/tex]
[tex]5b^3-10=6b^3-4b^2-10[/tex]
[tex]6b^3-5b^3-4b^2+10-10=0[/tex]
[tex]b^3-4b^2=0[/tex]
[tex]b^2(b-4)=0[/tex]
b² = 0 ⇒ b = 0
b - 4 = 0 ⇒ b = 4
Therefore, Option C is correct.
