Answer:
Step-by-step explanation:
Let the other be [tex] = x[/tex]
As the sum of the number is given as [tex] \frac {7}{8}[/tex]
And one number is [tex] \frac{3}{4}[/tex]
According to question
[tex] \frac{3}{4} +x = \frac{7}{8}[/tex]
Subtracting [tex] \frac{3}{4}[/tex] from both sides we get
[tex] \frac{3}{4} +x - \frac{3}{4} = \frac{7}{8} - \frac{3}{4}[/tex]
Taking LCM of 4 and 8 we get 8
And making
[tex] \frac{3}{4} [/tex] and [tex]\frac{7}{8}[/tex] like fraction by making denominator same.
Multiply [tex] \frac{3}{4} [/tex] by 2 in numerator and denominator and multiply [tex]\frac {7}{8}[/tex] by 1 in numerator and denominator we get
[tex]x= \frac{7}{8} - \frac{6}{8}[/tex]
[tex]x= \frac{7-6}{8}[/tex]
[tex]x =\frac{1}{8}[/tex]
Hence, the other number is [tex]\frac{1}{8}[/tex]
