Given that the average volume of water that flows over the falls each second is [tex]4.8 \times 10^5[/tex] gallons.
There are 3,600 seconds in one hour.
Thus, in one hour, [tex]4.8 \times 10^5\times3600=17280\times10^5=1.728\times10^9[/tex] gallons of water flows over the falls.
Therefore, the amount of water that flows over the falls is [tex]1.728\times10^9[/tex].