Find a point e on cd such that the ratio of ce to cd is 3/8

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kailysmith33 kailysmith33 · Answer 1 · 2017-10-04T01:33:54+02:00

The answer is -3 I took the test and I put a different answer that this cite told me to use and it was wrong

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ChiKesselman ChiKesselman · Answer 2 · 2019-10-08T20:53:13+02:00

Answer:

[tex]x = \displaystyle\frac{3x_2 + 5x_1}{8}, y = \displaystyle\frac{3y_2 + 5y_1}{8}[/tex]

Step-by-step explanation:

We are given the following information:

The point E on CD such that the ratio of CE to CD is 3:8.

Thus E divides CD into ratio 3:5.

Let [tex](x_1,y_1)[/tex] be the coordinate of C and [tex](x_2,y_2)[/tex] be the coordinates of D.

Section formula:

Let (x,y) be the coordinates of E, then,

[tex]x = \displaystyle\frac{mx_2 + nx_1}{m+n}, y = \displaystyle\frac{my_2 + ny_1}{m+n}[/tex],

where m:n is the ration where point E divides CD into.

Here, m:n = 3:5

Putting these values, we get,

[tex]x = \displaystyle\frac{3x_2 + 5x_1}{8}, y = \displaystyle\frac{3y_2 + 5y_1}{8}[/tex]