Respuesta :
empirical formula C2H3→ possible
Since the molecular formula of butyne or butadiene C4H6 supports the empirical formula
C2H3
Since the molecular formula of butyne or butadiene C4H6 supports the empirical formula
C2H3
Answer : [tex] C_{2}H_{3}[/tex] or 3.97
Explanation : As the the molar mass of carbon and hydrogen are ;
C=12 g/mol and H =1 g/mol
So, When Carbon Hydrogen mass ratio is 11.89
Then ratio of no. of atoms of C and H is given by [tex]\frac{C}{H}[/tex] = [tex]\frac{11.89}{12}/ \frac{1}{1}[/tex]
Which will be ≅ 1
So empirical formula C H is now possible
When Carbon Hydrogen mass ratio is taken as 3.97
The ratio of no. Of atoms of C and H is given by [tex]\frac{C}{H}[/tex] = [tex]\frac{3.97}{12}/ \frac{1}{1}[/tex]
which gives the answer as [tex]\frac{1}{3}[/tex]
So empirical formula [tex] CH_{3} [/tex] is possible
It can be cross verified as [tex]\frac{11.91}{3.97}[/tex] ≅ 2.99.
Therefore 3.97 is the correct answer and the empirical formula will be as[tex] CH_{3} [/tex] or [tex] C_{2}H_{6} [/tex]