The diagonals are perpendicular because the product of their slope is -1, and their midpoint is same (2,2). Hence, it is proved that the diagonals of the given square are perpendicular bisectors of each other.
Given information:
The square with vertices P (0,4), Q (4,4), R (0,0) and S (4,0).
It is required to prove that the diagonals of the given square are perpendicular bisectors.
First, calculate the slope of the diagonals.
The slope of diagonal PS will be,
[tex]m = \dfrac{0-4}{4-0}\\m = -1[/tex]
So, the slope of diagonal PS is -1.
The slope of diagonal QR will be,
[tex]m' = \dfrac{0-4}{0-4}\\m' = 1[/tex]
So, the slope of diagonal QR is 1.
From the slope of the diagonals, the diagonals are perpendicular because the product of slope is -1.
Now, it is required to find the mid-point of the diagonals.
The midpoint of PS will be,
[tex](x,y)=(\dfrac{0+4}{2},\dfrac{4+0}{2})=(2,2)[/tex]
Midpoint of QR will be,
[tex](x,y)=(\dfrac{4+0}{2},\dfrac{4+0}{2})=(2,2)[/tex]
So, the midpoint of both the diagonals is also same.
Therefore, it can be said that the diagonals are perpendicular because the product of their slope is -1, and their midpoint is same (2,2). Hence, it is proved that the diagonals of the given square are perpendicular bisectors of each other.
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https://brainly.com/question/3417399
