Mrs. Synder must choose two of her homeroom students to be class representatives. The class consists of 13 girls and 9 boys. Approximately what percent chance is there that the first student chosen is a boy and the second student chosen is a girl? (Round to the nearest percent)

A. 10%

B. 25%

C. 22%

D. 15%

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q851481 q851481 · Answer 1 · 2017-10-04T17:25:51+02:00

9/22 x 13/21 = 0.25 = 25% B

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JeanaShupp JeanaShupp · Answer 2 · 2019-09-24T07:02:14+02:00

Answer: B. 25%

Step-by-step explanation:

Given : Number of boys in the class = 13

Number of girls in the class = 9

Total students = 13+9=22

Now, the number of ways to choose first boy then a girl =[tex]13\times9=117[/tex] (1)

Number of ways to choose nay two students :-

[tex]{22}P_{2}=\dfrac{22!}{(22-2)!}\\\\=\dfrac{22\times21\times20!}{20!}=462[/tex] (2)

Now, the probability that the first student chosen is a boy and the second student chosen is a girl :-

[tex]\dfrac{117}{462}=0.253246753247\approx0.25[/tex] [Divide (1) by (2)]

In percent , [tex]0.25\times100=25\%[/tex]

Hence, approximately 25% chance that the first student chosen is a boy and the second student chosen is a girl.