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An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirror. The height of the image produced by the mirror, to the nearest tenth, is cm.

Respuesta :

Answer:

-3.2

Explanation:

hamzaahmeds

This question involves the concept of magnification and image height.

The image height is "3.2 cm".

What is Magnification?

The magnification of a mirror can be given as the ratio of height of image to the height of object. It can also be given as the ratio of the distance of image from mirror to the distance of object from the mirror.

[tex]M = \frac{h_i}{h_o}=\frac{q}{p}[/tex]

where,

  • M = magnification
  • [tex]h_i[/tex] = image height = ?
  • [tex]h_o[/tex] = object height = 8 cm
  • q = image distance = 16 cm
  • p = object distance = 40 cm

Therefore,

[tex]\frac{h_i}{8\ cm}=\frac{16\ cm}{40\ cm}\\\\h_i=\frac{(8\ cm)(16\ cm)}{40\ cm}[/tex]

[tex]h_i=3.2\ cm[/tex]

Learn more about magnification here:

https://brainly.com/question/3851549

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