The givens are as follows:
initial velocity (vi) = 6 m/sec
acceleration = -9.8 m/sec^2 (the negative sign refers to the direction)
final velocity (v) = 1.1 m/sec
initial position (xi) = 0 meters
Now, we will use the equations of motion to get the displacement as follows:
v = vi + at
1.1 = 6 - 9.8t
9.8t = 6-1.1 = 4.9
t = 0.5 sec
x = xi + vit + 0.5at^t
x = 0 + (6)(0.5) + 0.5(-9.8)(0.5)^2
x = 1.775 meters
