The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of length fraction 1 over 7 unit and width fraction 1 over 2 unit?

Respuesta :

P = 2(L + W)
L = 1/7
W = 1/2

P = 2(L + W)
P = 2(1/7 + 1/2)
P = 2(2/14 + 7/14)
P = 2(9/14)
P = 18/14 which reduces to 9/7 or 1 2/9 <==

Answer:

perimeter of rectangle is 9/7 units.

Step-by-step explanation:

The perimeter of a rectangle is given by

Perimeter = 2(length + width)

Given that

[tex]length=\frac{1}{7}\\\\width=\frac{1}{2}[/tex]

Substituting these values in the above formula

[tex]P=2(\frac{1}{7}+\frac{1}{2})[/tex]

Add the fractions. The LCD is 14. So, multiply and divide by 14

[tex]P=\frac{2}{14}(\frac{1}{7}\times14+\frac{1}{2}\times14)\\\\P=\frac{1}{7}(2+7)\\\\P=\frac{9}{7}[/tex]

Thus, perimeter of rectangle is 9/7 units.