A = $9.99, the amount needed after 1 year
r = 0.018% = 0.00018, interest rate
n = 12, compoundings per year
t = 1, one year duration
Let P = required balance at the beginning of the year.
Then
[tex]P(1+ \frac{r}{n} )^{nt} = A[/tex]
P(1 + 0.00018/12)¹² = 9.99
1.00018P = 9.99
P = $9.988 ≈ $9.99
Answer: $9.99