Respuesta :
The parabola is facing downward that is why it is going to take the equation,
x² = -4ay
If we take the point at which the maximum height is reached be the origin, the starting point of the parabola from the left is going to be (-15, -10).
Substituting the values of x and y to the equation,
(-15)² = -4(a)(-10)
a = 5.625
The goal is at the point equal to (27 - 15, 8 - 10) or (12, -2). We are to substitute these values to the equation and see if the equation is satisfied.
x² = -4(5.625)(y)
12² = -4(5.625)(-2)
144 ≠ 45
Thus, the ball will not land in the goal.
x² = -4ay
If we take the point at which the maximum height is reached be the origin, the starting point of the parabola from the left is going to be (-15, -10).
Substituting the values of x and y to the equation,
(-15)² = -4(a)(-10)
a = 5.625
The goal is at the point equal to (27 - 15, 8 - 10) or (12, -2). We are to substitute these values to the equation and see if the equation is satisfied.
x² = -4(5.625)(y)
12² = -4(5.625)(-2)
144 ≠ 45
Thus, the ball will not land in the goal.
Answer:
The ball will land inside the goal.
Step-by-step explanation:
Given : The flight of the ball is modeled by a parabola.
To find : Will the soccer ball land in the goal?
Solution :
Let the equation of the parabola be,
[tex]y=a(x-h)^2+k[/tex]
Where, (h,k) are the vertex of the parabola,
According to question,
A soccer player who is 27 feet from a goal.
Let A be the point where player stand i.e, (27,0)
The height of the goal is 8 feet.
Let B be the point of height of goal i.e, (0,8)
The ball reached a maximum height of 10 feet when it was 15 feet from the soccer player.
The distance from goal to the distance 15 feet away from the player is
27-15=12 feet
Let C be the point with maximum height i.e, (12,10)
C is the vertex of the parabola and A is the point on the parabola.
Then, The equation of parabola is
[tex]y=a(x-12)^2+10[/tex]
Point A satisfy the equation,
[tex]0=a(27-12)^2+10[/tex]
[tex]0=a(15)^2+10[/tex]
[tex]a=-\frac{10}{225}[/tex]
Substitute back in equation,
[tex]y=-\frac{10}{225}(x-12)^2+10[/tex]
Now, we find the y-intercept of the equation i.e, x=0,
[tex]y=-\frac{10}{225}(0-12)^2+10[/tex]
[tex]y=-\frac{10}{225}(144)+10[/tex]
[tex]y=3.6[/tex]
If the y-intercept is greater than 8 then the ball will land outside the goal.
If the y-intercept is less than 8 then the ball will land inside the goal.
As 3.6<8
Therefore, The ball will land inside the goal.
Refer the attached figure below.
