Respuesta :
[tex]\bf \textit{arc's length}\\\\
s=\cfrac{\pi \theta r}{180}\quad
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=16\\
s=19.36
\end{cases}\implies 19.36=\cfrac{\pi \theta 16}{180}\implies \cfrac{19.36\cdot 180}{16\pi }=\theta[/tex]
I believe you're going to be working in degrees, there is a different scaling factor for radians (θ/2pi). The arc length formula is just the formula for the circumference of a circle scaled by how many degrees of the circle you have. In this case, radius is 16, arc length is 19.36. Then we have:
[tex]19.36=2 \pi (16)\frac{\theta}{360}[/tex]
Solve for θ.
[tex]19.36=2 \pi (16)\frac{\theta}{360}[/tex]
Solve for θ.