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Find the zeros with multiplicity for the function p(x) = (x^3 – 8)(x^5 – 4x^3)

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Respuesta :

x^3 - 8 = 0   Gives  us a zero of x = 2

x^5 - 4x^3 = 0   gives  another zero  of x = 0

x^3(x^2 - 4)  = 0  gives 2 more zeros (x^2 = 4  so x = 2, -2)

So the answer is  -2, 0 and 2 multiplicity 2

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