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You reach into a bag of coins and withdrew two coins without replacement. What is the probability you withdrew a nickel and then a dime if the bag held ten pennies, six nickels, and five dimes?









1.30/44
2.5/14
3.1/14

Respuesta :

Answer:

Option 3. 1/14

Step-by-step explanation:

The bag held some coins that are

pennies = 10

nickels = 6

dimes = 5

total coins = 10 + 6 + 5 = 21 coins

You drew 2 coins without replacement,

so the probability that first draw will be nickel = [tex]P_{1}[/tex] = 6/21 = 2/7

Second draw will be a dime  = [tex]P_{2}[/tex] = 5/20 = 1/4

P = [tex]\frac{2}{7}[/tex] × [tex]\frac{1}{4}[/tex] = 2/28 = 1/14

Option 3. 1/14 would be the answer.

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