Respuesta :

[tex]f(x)=x^2-6x+8\\\\the\ zeros:f(x)=0\to x^2-6x+8=0\\\\x^2\underbrace{-4x-2x}_{=-6x}+8=0\\\\x\cdot x-x\cdot4-2\cdot x-2\cdot(-4)=0\\\\x(x-4)-2(x-4)=0\\\\(x-4)(x-2)=0\iff x-4=0\ or\ x-2=0\\\\therefore\\\\\boxed{x=4\ or\ x=2}[/tex]
kaleag1205

Answer:

The answer is C.

Step-by-step explanation:

I took the test and got it right