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Neglecting air resistance (that is, if you and the Eiffel Tower were in a giant vacuum chamber), the bagel would take 7.804 s to hit you on the head.
I will assume that you are 1.8 m tall, so the distance the bagel falls before it hits you on the head is
300.5 m - 1.8 m = 298.7 m
One of the important equations relating distance and acceleration is
s = v₀ +½at², where
s = distance,
v₀ = initial velocity,
a = acceleration, and
t = time.
I also assume that the person at the top of the tower didn't throw the bagel down at you, so v₀ = 0.
a is the acceleration due to gravity, which is 9.8099 m·s⁻² in Paris.
s = v₀ + ½ at²
298.7 m = 0 + ½ × 9.8099 m·s⁻² × t²
298.7 = 4.9050 t² s⁻²
t² = [tex] \frac{298.7 \text m}{ 4.9050 \text s^{-2}} [/tex] = 60.898 s²
t = [tex] \sqrt{60.898 s^{2}}[/tex] = 7.804 s
I will assume that you are 1.8 m tall, so the distance the bagel falls before it hits you on the head is
300.5 m - 1.8 m = 298.7 m
One of the important equations relating distance and acceleration is
s = v₀ +½at², where
s = distance,
v₀ = initial velocity,
a = acceleration, and
t = time.
I also assume that the person at the top of the tower didn't throw the bagel down at you, so v₀ = 0.
a is the acceleration due to gravity, which is 9.8099 m·s⁻² in Paris.
s = v₀ + ½ at²
298.7 m = 0 + ½ × 9.8099 m·s⁻² × t²
298.7 = 4.9050 t² s⁻²
t² = [tex] \frac{298.7 \text m}{ 4.9050 \text s^{-2}} [/tex] = 60.898 s²
t = [tex] \sqrt{60.898 s^{2}}[/tex] = 7.804 s
The time taken for the croissant to hit you on the head assuming you are 1.5 m tall is 7.73 s
Considering the question given above, your height was not stated.
Let your height be 1.5 m
Thus, the height of the Eiffel Tower to your head will be:
Height (h) = (Total height of tower) – (Your assumed height)
Total height of tower = 300.5 m
Your assumed height = 1.5 m
Height (h) = 300.5 – 1.5
Height (h) = 299 m
Finally, we shall determine the time taken for the croissant to hit you on the head.
Height (h) = 299 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
H = ½gt²
299 = ½ × 10 × t²
299 = 5 × t²
Divide both side by 5
[tex]t^{2} = \frac{299}{5}\\\\t^{2} = 59.8[/tex]
Take the square root of both side
[tex]t = \sqrt{59.8}[/tex]
t = 7.73 s
Therefore, the time taken for the croissant to hit you on the head assuming you are 1.5 m tall is 7.73 s
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