A farm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the trailer ( ignore friction.)

Respuesta :

The force exerted by gravity is:

F = m g

F = 3300 kg * 9.8 m/s^2

F = 32,430 N

 

The force exerted due to the inclined plane is:

F tractor = 32,430 N * sin 14

F tractor = 7,823.75 N      (answer)