Bismuth oxide reacts with carbon to form bismuth metal: bi2o3(s) + 3c(s) → 2bi(s) + 3co(g) when 689 g of bi2o3 reacts with excess carbon, (a) how many moles of bi form? 2.957 mol bi (b) how many grams of co form? g co

Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:

2 : 3

Using the method of ratios,

2 : 3
2.957 : CO

CO = (3 * 2.957) / 2
CO = 4.4355

4.436 moles of carbon monoxide will be formed

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ardni313 ardni313 · Answer 2 · 2019-07-14T11:37:40+02:00

CO mass = 4,435. 18 = 79,839 grams

Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example the substance level or molecular formula of hydrate.

In stockiometry therein includes

relative atomic mass (Ar) and relative molecular mass (Mr)

Mr. AxBy = (x.Ar A + y. Ar B)

Reactions that occur:

Bi₂O₃ (s) + 3C (s) → 2Bi (s) + 3CO (g)

We specify mole Bi₂O₃

Mr Bi₂O₃ = 2. ar bi + 3. Ar O

Mr Bi₂O₃ = 2. 209 + 3. 16

Mr. Bi₂O₃= 466

mole Bi₂O₃ = gram / Mr

mole = 689/466

mole 1.4785

A. Comparison of Bi reaction coefficients: Bi₂O₃ = 1: 2, then Bi moles = 2. 1,4785 = 2, 957

Comparison of Bi reaction coefficients: Bi₂O₃ = 1: 2,

B. While the number of moles CO = 3 x 1.4785 = 4,435

Mr. CO = 12 + 16 = 18

mass CO = mole. Mr

CO mass = 4,435. 18 = 79,839 grams

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