vivianailadelacruz vivianailadelacruz
  • 21-10-2017
  • Mathematics
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how do you factor 30n^2b-87nb+30b?

Respuesta :

altavistard
altavistard altavistard
  • 23-10-2017
It's not clear whether you meant 30n^(2b) or [30n^2] b.

I will assume the latter.

b can then be factored out of all  three terms, resulting in 

b [30n^2 - 87n + 30]     = b [ 3 ] [10n^2 - 29n + 10 ]

Can you factor this further?
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