Answer:
A. [tex](-1,-2)[/tex]
D. [tex](-6,0)[/tex]
E. [tex](-5,-1)[/tex]
Step-by-step explanation:
We have been given an inequality [tex]x+3y\geq -8[/tex]. We are asked to find the ordered pairs that are solution to the given inequality.
Let us check each ordered pair by substituting in the given inequality.
A. [tex](-1,-2)[/tex]
[tex]-1+3(-2)\geq -8[/tex]
[tex]-1-6\geq -8[/tex]
[tex]-7\geq -8[/tex]
Since the given inequality holds true, therefore, ordered pair [tex](-1,-2)[/tex] is a solution for the inequality.
B. [tex](-16,2)[/tex]
[tex]-16+3(2)\geq -8[/tex]
[tex]-16+6\geq -8[/tex]
[tex]-10\geq -8[/tex]
Since the given inequality is not true, therefore, ordered pair [tex](-16,2)[/tex] is not solution for the inequality.
C. [tex](0,-3)[/tex]
[tex]0+3(-3)\geq -8[/tex]
[tex]0-9\geq -8[/tex]
[tex]-9\geq -8[/tex]
Since the given inequality is not true, therefore, ordered pair [tex](0,-3)[/tex] is not solution for the inequality.
D. [tex](-6,0)[/tex]
[tex]-6+3(0)\geq -8[/tex]
[tex]-6+0\geq -8[/tex]
[tex]-6\geq -8[/tex]
Since the given inequality holds true, therefore, ordered pair [tex](-6,0)[/tex] is a solution for the inequality.
E. [tex](-5,-1)[/tex]
[tex]-5+3(-1)\geq -8[/tex]
[tex]-5-3\geq -8[/tex]
[tex]-8\geq -8[/tex]
Since the given inequality holds true, therefore, ordered pair [tex](-5,-1)[/tex] is a solution for the inequality.
