Respuesta :

kritter1
We know that the basic equation of exponential equation equation is; 

y=ab^x 

Where a is the y-intercept/starting point and b is the value that x exponentially grows or decays. 

From the given equation, the two graphs with other intercepts (not 4) can be removed. 

Since b is between 0 and one, this function should be decaying. 

Next calculate the value of x when y=1. 

1=4(0.5)^x 
1/4=(1/2)^x 
log₀₋₅(1/4)=x 
2=x

Check which of the graphs have y=1, x=2. This would be the second graph, which would represent the equation y=4(0.5)^x 

Hope I helped :) 
lhmarianateixeira

In this exercise we have to be aware of the type of graph we have and identify its formula, like this:

The second graph

As it is a graph of the equation of an exponential, we have that its form is given by:

[tex]y=ab^x[/tex]

Where:

  • y-intercept/starting point
  • b is the value
  • x exponentially grows or decays.

Calculating the value of X when Y is equal to 1, we have:

[tex]1=4(0.5)^x \\1/4=(1/2)^x \\log_{0.5}(1/4)=x \\x=2[/tex]

See more about graphs at brainly.com/question/14375099