Respuesta :
Reacting solutions of HCl and NaOH in a third beaker will produce sodium chloride (NaCl), an ionic salt, and water (H₂O). The balanced chemical equation is:
HCl + NaOH → NaCl + H₂O
The third beaker would then show an aqueous solution since sodium chloride easily dissolves in water. The ions that would be present in the beaker are Na⁺ and Cl⁻ ions.
HCl + NaOH → NaCl + H₂O
The third beaker would then show an aqueous solution since sodium chloride easily dissolves in water. The ions that would be present in the beaker are Na⁺ and Cl⁻ ions.
The third beaker will contain [tex]\boxed{{\text{N}}{{\text{a}}^ + }{\text{ and C}}{{\text{l}}^ - }\;{\text{ions}}}[/tex].
Further Explanation:
Neutralization reaction:
It is the reaction that occurs between an acid and a base in order to form salt and water. It is named so as the excess amount of hydrogen or hydroxide ions present in the solution are being neutralized in such reactions. It is used to decrease the acidity in the stomach, wastewater treatment, antacid tablets and to control the pH of soil. An example of neutralization reaction is,
[tex]{\text{Acid}}+{\text{Base}}\to{\text{Salt}}+{\text{Water}}[/tex]
HCl is present in one beaker while there is NaOH in the other beaker. These two are allowed to react with each other and the products formed after the reaction are present in a third beaker.
HCl is a strong acid while NaOH is a strong base.
HCl dissociates into its ions as follows:
[tex]{\text{HCl}} \to {{\text{H}}^+}+{\text{C}}{{\text{l}}^-}[/tex]
The dissociation of NaOH occurs as follows:
[tex]{\text{NaOH}} \to {\text{N}}{{\text{a}}^+}+{\text{O}}{{\text{H}}^-}[/tex]
The [tex]{{\text{H}}^ + }[/tex] ions released by HCl combine with [tex]{\text{O}}{{\text{H}}^ - }[/tex] ions of NaOH and water is formed. So [tex]{\text{N}}{{\text{a}}^ + }[/tex] and [tex]{\text{C}}{{\text{l}}^-}[/tex] combine with each other to form salt NaCl.
The complete reaction is as follows:
[tex]{\text{HCl}}\left({aq}\right)+{\text{NaOH}}\left( {aq}\right)\to{{\text{H}}_2}{\text{O}}\left(l\right)+{\text{NaCl}}\left({aq}\right)[/tex]
So the third beaker will contain NaCl and [tex]{{\text{H}}_2}{\text{O}}[/tex] as these are the products formed after neutralization reaction of HCl and NaOH. NaCl is an ionic compound so it will dissociate into [tex]{\text{N}}{{\text{a}}^+}[/tex] and [tex]{\text{C}}{{\text{l}}^-}[/tex] ions and therefore third beaker contains [tex]{\text{N}}{{\text{a}}^+}[/tex] and [tex]{\text{C}}{{\text{l}}^ - }[/tex] ions in it.
Learn more:
1. Balanced chemical equation https://brainly.com/question/1405182
2. Oxidation and reduction reaction https://brainly.com/question/2973661
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Chemical reaction and equation
Keywords: neutralization reaction, salt, HCl, NaCl, H2O, NaOH, acid, base, beaker, third beaker, Na+, Cl-, strong acid, strong base.
