We need to find the height of the mirror to solve this problem. We know the area and width, so using the formula [tex]A=l*w[/tex], we have [tex]l=\frac{A}{w}[/tex]. Then:
[tex]l=\frac{11\frac{11}{16}}{2\frac{3}{4}}=\frac{187}{16}*\frac{4}{11}=\frac{17}{4}[/tex]
Since [tex]\frac{17}{4}[/tex] is less than 5, the mirror will fit.
