Respuesta :

x= 1st integer         x+2= 2nd integer
3x = 6(x+2)-6
distribute to get 3x=6x+12-6
12-6=6 so 3x=6x+6
subtract 6 from both sides to get 3x-6=6x
subtract 3x from both sides to get -6=6x-3x
subtract and get -6=3x
divide by three and x=-2 so x+2=0.