Respuesta :
Answer:- c. 0.5sin30°
Explanation:-
Let AB= 0.5 miles be the distance across the lake to 60º north of east.
AC= distance travel to the east
Now, in right ΔABC
[tex]sin60^{\circ}=\frac{AC}{AB}\\\\\Rightarrow\ AB=ACsin60^{\circ}\\\Rightarrow\ AB=0.5\ sin60^{\circ}[/tex]
Now Distance towards west [tex]AD=|\ -0.5\ sin60^{\circ}|[/tex] [distance is a positive quantity]
[tex]AD=0.5\ sin60^{\circ}[/tex]
[tex]AD=0.5\ cos(90^{\circ}-60^{\circ})[/tex] [Taking complementary angle of 60° ]
[tex]AD=0.5\ cos(30^{\circ})[/tex]
Thus C. is the right option.
