First, find the slope of the line y-Ax=B
y=Ax+B, so the slope is A, which is a constant.
Because the new line is parallel to the given line, so the slope is also A.
Next, write the new line in point-slope form:
(y-3)=A(x-(-7)) =>y-3=A(x+7)
You can write it into slope-intercept form if needed: y-3=Ax+7A =>y=Ax+7A+3
or standard form: y-Ax-7A-3=0
