A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground

The distance a falling object falls in some amount of time is

D = 1/2 a T²

If this flowerpot falls off a balcony on Earth, then 'a' is the
acceleration of gravity on Earth, and we can write

85 m = 1/2 (9.8 m/s²) T²

Divide each side by 4.9 m/s² :

85/4.9 s² = T²

Square root each side:

T = √(85/4.9) seconds

= 4.165 seconds .

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Eduard22sly Eduard22sly · Answer 2 · 2021-09-30T13:43:48+02:00

It will take 4.12 s for the flowerpot to fall to the ground.

From the question given above, the following data were obtained:

Height (h) = 85 m

Time (t) =?

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the flowerpot to fall to the ground can be obtained as follow:

H = ½gt²

85 = ½ × 10 × t²

85 = 5 × t²

Divide both side by 5

[tex]t^{2} = \frac{85}{5}\\\\t^{2} = 17[/tex]

Take the square root of both side

[tex]t = \sqrt{17}[/tex]

t = 4.12 s

Therefore, it will take 4.12 s for the flowerpot to fall to the ground.

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