Respuesta :
Since they are FEWER than 30 total cones, the sum of x small cones and y large one must be LESS THAN 30: x+y <30
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
[tex]y \geqslant 12[/tex]
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
[tex]y \geqslant 12[/tex]
Answer: The correct options are,
x+y < 30
y ≥ 12
Step-by-step explanation:
Here, x represent the number of small cones and y represent the number of large cones.
∵ Large cones are at least 12,
⇒ y ≥ 12,
Now, total cones = x + y
∵ There are fewer than 30 cones,
I.e. x + y < 30,
Now, number of cones can not be negative,
⇒ x, y ≥ 0