A gaseous compound having the empirical formula ch2 has a density of 1.88 g/l at stp. the molecular formula for this compound is (assuming ideal behavior):
The empirical formula is CH2
Density of ch2 = 1.88 g/l
Calculating the Molar mass = d x RT / p
Molar Mass = (1.88 x 0.0821x 273 K) / 1 = 42.13 g/mol
Molar mass of CH2 = 14.027 g/mol
Deducing the Multiple = 42.13 / 14.027 = 3
Multiplying the multiple 3 with CH2 is C3H6
So the compound is Propene.