The book slides from you to beth and then from beth to carlos, along the lines connecting these people. what is the work done by friction during this displacement?

Respuesta :

Note that          
          
W(friction) = - uk m g d          
          
Where          
          
uk =    0.2      
m = mass =    1.9   kg  
d = total distance = 8 m *2 =    16   m  
          
Thus,          
          
W(friction) =    -59.584   J

The answer is -59.584 J

The work done due to friction is [tex]\boxed{59.58{\text{ N}}}[/tex].

Further explanation:

Here, we have to calculate the total work done due to frictional force.

Frictional force is a non-conservative force and the work done by a non-conservative force is path dependent.

Given:

The mass of the physics book is [tex]1.9{\text{ kg}}[/tex].

Coefficient of friction between the book and floor is [tex]0.2[/tex].

The distance between observer that is (you) and Beth is [tex]8{\text{ m}}[/tex]

The distance between Beth and Carlos is [tex]8{\text{ m}}[/tex].

Formula and concept used:

The work done by the conservative force is equal to the product of force and the displacement.

Now, we will know about displacement,

Displacement: The shortest distance between the initial and final position of the object is known as displacement.

But, in case of the non-conservative forces, the work done is equal to the product of the force and the total distance travel by the object.

So, friction force can be calculated as,

[tex]{F_r} = \mu mg[/tex]

Here, [tex]m[/tex] is the mass of the book, [tex]\mu[/tex] is the coefficient of friction.

So, work done due to friction when observer slides the book to the Beth and Beth slides the book to Carlos.

[tex]\boxed{W = {F_r} \cdot d}[/tex]

Here, [tex]{F_r}[/tex] is the friction force, [tex]d[/tex] is the total distance travel against friction force.

[tex]\boxed{\begin{aligned}d&=8+8\\&=16\text{ m}\end{aligned}}[/tex]

Substitute the value of [tex]{F_r}[/tex] in above equation.

[tex]W = \mu mgd[/tex]                                                                       …… (1)

Calculation:

Substitute [tex]0.2[/tex] for [tex]\mu[/tex], [tex]1.9{\text{ kg}}[/tex] for [tex]m[/tex] and [tex]16{\text{ m}}[/tex] for [tex]d[/tex] in equation (1).

[tex]\begin{aligned}W&=\left( {0.2} \right)\left( {1.9} \right)\left( {9.8} \right)\left({16}\right)\\&=59.58{\text{ N}}\\\end{gathered}[/tex]

The work done due to friction is [tex]\boxed{59.58{\text{ N}}}[/tex].

Learn more:

1. Acceleration against friction: https://brainly.com/question/7031524

2. Water is a compound because: https://brainly.com/question/4636675

3. Conservation of momentum during collision https://brainly.com/question/9484203

Answer detail:

Grade: Senior School

Subject: Physics

Chapter: Work and Energy

Keywords:

Book slide, Beth, Carlos, work done, friction, four corners, square, 8m length, 59.58 N, connecting these people, displacement.

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