francescamuzz25
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The holding tanks are congruent. Each is in the shape of a cylinder that has been cut in half vertically. The bottom of each tank is a curved surface and the top of the pool is a flat surface. What is the volume of both tanks if the radius of tank #1 is 30 feet and the height of tank #2 is 110 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.

The holding tanks are congruent Each is in the shape of a cylinder that has been cut in half vertically The bottom of each tank is a curved surface and the top class=

Respuesta :

W0lf93
Volume of cylinder = height * pi * radius^2 volume of tank = 1/2(volume of cylinder) Volume of tank1 = 1/2(110ft * pi * (30ft^2)) = 49,500 pi ft^3 Volume of tank2 = 1/2(110ft * pi * (30ft^2)) = 49,500 pi ft^3 Volume combined = 49,500 pi ft^3 + 49,500 pi ft^3 = 99,000 pi ft^3 You could also realize that 2 congruent half-cylinders make 1 whole cylinder 110ft * pi * (30ft^2) = 99,000 ft^3 Volume ~= 311,018 ft^3

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