Answer:
[tex]W=K_f -K_i = \frac{1}{2}mv_f^2 -\frac{1}{2}mv_i^2[/tex]
Explanation:
The work-energy theorem states that the amount of work done is equal to the variation of kinetic energy of the object, therefore:
[tex]W=K_f -K_i = \frac{1}{2}mv_f^2 -\frac{1}{2}mv_i^2[/tex]
Where:
m is the mass of the object
[tex]v_i[/tex] is the initial velocity of the object
[tex]v_f[/tex] is the final velocity of the object
