The volume of the partial cone is the volume of the entire funnel minus the volume of the cylindrical part.
The volume of a cylinder is given by:
[tex]V=\pi r^2h[/tex]
where: r is the radius of the cylinder and h is the height of the cylinder.
Given that the cylindrical part of the funnel has a height of 1.5 cm and a diameter of 1.5 cm, thus the radius is 1.5 / 2 = 0.75 cm and the volume is given by:
[tex]V=\pi(0.75)^2(1.5)=0.84375\pi=2.65072cm^3[/tex]
Therefore, the volume of the partial cone is given by 16.59375 - 2.65072 = 13.94303 cubic cm.
