The chemical formula of the compound produced from the reaction of the anion (a negatively charged ion) with formula of A⁻ᵃ and a cation (a positively charged ion) with formula B⁺ˣ can be written as,
BₐAₓ
The answers to the questions above:
Row 2, Column 2: Na⁺ and NO⁻³ : Na₃NO
Row 2, Column 3: Ca²⁺ and NO⁻³ : Ca₃(NO)₂
Row 2, Column 4: Fe³⁺ and NO⁻³ : Fe₃(NO)₃
This can be furthered reduced to: FeNO
Row 2, Column 5: NH⁴⁺ and NO⁻³ : (NH)₃(NO)₄
Row 2, Column 6: Sn⁴⁺ and NO⁻³ : Sn₃(NO)₄
For the third row anion, S₂⁻
Row 3, Column 2: Na⁺ and S₂⁻ : NaS₂
Row 3, Column 3: Ca²⁺ and S₂⁻ : CaS₄
Row 3, Column 4: Fe³⁺ and Si₂⁻ : FeS₆
Row 3, Column 5: NH⁴⁺ and S₂⁻ : NHS₈
Row 3, Column 6: Sn⁴⁺ and S₂⁻ : SnS₈
For Row 4 anion, PO₃⁻⁴
Row 4, Column 2: Na⁺ and PO₃⁻⁴: Na₄PO₃
Row 4, Column 3: Ca²⁺ and PO₃⁻⁴ : Ca₄(PO₃)₂
Row 4, Column 4: Fe³⁺ and PO₃⁻⁴ : Fe₄(PO₃)₃
Row 4, Column 5: NH⁺⁴ and PO₃⁻⁴ : (NH)₄(PO₃)₄
This can be further simplified into NHPO₃
Row 4, Column 6: Sn⁴⁺ and PO₃⁻⁴ : Sn₄(PO₃)₄
This can be further simplified into SnPO₃
For Row 5 anion, CO₂⁻³
Row 5, Column 2: Na⁺ and CO₂⁻³ : Na₃CO₂
Row 5, Column 3: Ca²⁺ and CO₂⁻³ : Ca₃(CO₂)₂
Row 5, Column 4: Fe³⁺ and CO₂⁻³ : Fe₃(CO₂)₃
this can be further simplified into FeCO₂
Row 5, Column 5: NH⁴⁺ and CO₂⁻³ : (NH)₃(CO₂)₄
Row 5, Column 6: Sn⁴⁺ and CO₂⁻³ : Sn₃(CO₂)₄