Answer: C) mC > mA > mB is correct regarding the angles of the triangle ABC.
Step-by-step explanation:
Given: In Δ ABC, the side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3.
AB=4p-1 , AC=p+4 , BC=3p
where p+4 < 3p [as p≥3]
3p < 4p-1 [as p≥3]
⇒ 4p-1> 3p > p+4
⇒AB>BC>AC
Angle opposite to AB ,BC and AC is m∠C ,m∠A and m∠B.
Therefore mC > mB > mA [∵Angle opposite to greater side is greater]
Thus , mC > mA > mB is correct regarding the angles of the triangle ABC.
