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Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?
(u + 2)2 + 5(u + 2) – 6 = 0 where u = (x – 2) u2 + 4 + 5u – 6 = 0 where u = (x – 2) u2 + 5u – 6 = 0 where u = (x + 2) u2 + u – 6 = 0 where u = (x + 2)

Respuesta :

calculista

we have

[tex](x+2)^{2} +5(x+2)-6=0[/tex]

Let

[tex]u=(x+2)[/tex]

Substitute in the expression

[tex](u)^{2} +5(u)-6=0[/tex]

therefore

the answer is

[tex](u)^{2} +5(u)-6=0[/tex] is equivalent to [tex](x+2)^{2} +5(x+2)-6=0[/tex]

Answer: C

Step-by-step explanation:

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