Respuesta :
[tex]\bf s=\cfrac{sa}{6}\qquad \cfrac{\stackrel{larger}{side}}{\stackrel{smaller}{side}}\implies \cfrac{\quad \frac{180}{6}\quad }{\frac{120}{6}}\implies \cfrac{180}{6}\cdot \cfrac{6}{120}\implies \cfrac{180}{120}\implies \cfrac{3}{2}[/tex]
they're on a ratio of 3:2, so if the small is 2, the large one is 3, and if the small one is 120, the large one is 180.
on a 3:2 ratio, 3 is larger than 2 by 1 unit, 1 is 50% of 2, or half, so the longer side is 50% larger.
they're on a ratio of 3:2, so if the small is 2, the large one is 3, and if the small one is 120, the large one is 180.
on a 3:2 ratio, 3 is larger than 2 by 1 unit, 1 is 50% of 2, or half, so the longer side is 50% larger.
Answer with explanation:
Side of cube = S
Surface Area of Cube = S.A
Relation between Side of a cube and surface area
[tex]S=\frac{S.A}{6}[/tex]
→If surface area of cube =180 Square meters
Side of cube (S)
[tex]S_{1}=\frac{180}{6}\\\\=30[/tex] meters
→ If surface area of cube =120 Square meters
Side of cube (S)
[tex]S_{2}=\frac{120}{6}\\\\=20[/tex] meters
[tex]S_{1}-S_{2}=30 -20=10\\\\S_{1}=S_{2}+10[/tex]
Side of cubic having surface area 180 square meters is greater by 10 meters, than a cube with the surface area of 120 square meters.
