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a cannonball with a mass of 1.0 kilogram is fired horizontally from a 500.- kilogram cannon, initially at rest, on a horizontal, frictionless surface. The cannonball is acted on by an average force of 8.0x10^3 newtons for 1.0x10^-1 second. (a) What is the magnitude of the average net force acting on the cannon? (b) Determine the acceleration of the cannon ball.

Respuesta :

barnuts

(a) According to Newton’s third law, for every action there is an equal yet opposite reaction. In this case, the cannonball is affected by 8.0x10^3 newtons in one direction. Now the cannon must also be affected by the same amount of net force on the opposite direction.

- 8.0x10^3 Newtons (the negative symbol only shows that it is opposite direction)

 

(b) We solve this using the formula:

F = m a

8.0x10^3 N = (1.0 kg) a

a = 8,000 m/s^2

lhmarianateixeira

In this exercise we will use the knowledge of Newton's laws to be able to answer about the force, in this way:

A) opposite direction to the movement.

B) a = 8,000 m/s^2

So, recalling Newton's concept of force, we have:

One newton corresponds to the force exerted on a body of mass equal to 1 kg that induces an acceleration of 1 m/s² in the same direction as the force.

A)The magnitude of a force is linked to its direction, so we will have that force is in the opposite direction to the movement.

B) We solve this using the formula:

[tex]F = m a\\8.0*10^3 N = (1.0 kg) a\\a = 8,000 m/s^2[/tex]

See more about force at brainly.com/question/26115859

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