Another component of acid rain is nitric acid, which forms when NO2, also a pollutant, reacts with oxygen and water according to the simplified equation 4NO2(g)+O2(g)+2H2O(l) → 4HNO3(aq) The generation of the electricity used in a medium-sized home produces about 14 kg of NO2 per year. Part A Assuming that there is adequate O2 and H2O, what mass of HNO3, in kg, can form from this amount of NO2 pollutant?

More than one element bonded together is known as a compound.Sum of total mass of molecule measure in gram which constitutes the atom of molecule known as molar mass. Gram per mole is an S.I. unit of molar mass.Molarity of a solution define as the number of moles of solute per litre solution.

For the provided reaction:

[tex]4{\text{N}}{{\text{O}}_2}({\text{g}})+{{\text{O}}_2}({\text{g}})+2{\text{N}}{{\text{O}}_2}({\text{l}})\to4{\text{N}}{{\text{O}}_3}({\text{aq}})[/tex]

Oxygen and water found in abundance. So, the NO2 is known as a limiting reagent as it is responsible for limiting the product formation. The moles of NO2is calculated with the help of the formula:

[tex]\begin{gathered}{\text{Number of moles=}}\frac{{{\text{given mass}}}}{{{\text{molar mass}}}}\hfill\\\begin{array}{*{20}{l}}{{\text{Given mass }}=14{\text{ kg}}=14000{\text{ grams}}}\\{{\text{Molar mass}}=46{\text{g/mol}}}\end{array}\hfill\\\end{gathered}[/tex]

Inserting the values in the formula,

[tex]\begin{aligned}{\text{Moles of N}}{{\text{O}}_2}=\frac{{14000}}{{46}}\\=304.34\end{aligned}[/tex]

By the help of Stoichiometry,

4 moles of NO2 will generate 4 moles of HNO3

This means that 304.34 moles of will generate,

[tex]\begin{gathered}=\frac{4}{4}\times304.34\hfill\\=304.34\hfill\\\end{gathered}[/tex]

In order to calculate the mass of HNO3, first equation can be used and we will get,

[tex]\begin{aligned}{{\text{Molar mass of HN}}{{\text{O}}_3}&={\text{ }}63{\text{ g/mol}}}\\{&=304.34\times63}\\{&=19173.42\text{ g}{\text{ or }}19.17{\text{ Kg}}}\end{aligned}[/tex]

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Answer Details:

Grade: High School

Subject: Chemistry

Chapter: Solution

Keywords:

Stoichiometry, number of moles, nitric oxide, given mass, molar mass, equation, moles, oxygen, water,unit, element, compound, atom, molarity, solution.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-10-29T07:38:30+02:00

19.15 Kg of HNO3 is produced.

The equation of the reaction is;

4NO2(g) + O2(g) + 2H2O(l) → 4HNO3(aq)

Mass of NO2 produced = 14 kg

Molar mass of NO2 = 46 g/mol

Number of moles of NO2 = 14 × 10^3 g/46 g/mol

= 304 moles

Since oxygen gas and water are present in excess, the production of HNO3 depends on the amount of NO2. Hence;

4 moles of NO2 yields 4 moles of HNO3

304 moles of NO2 yields 304 moles of HNO3

Mass of HNO3 produced = Number of moles of HNO3 × molar mass of HNO3

Molar mass of HNO3 = 63 g/mol

Mass of HNO3 produced = 304 moles of HNO3 × 63 g/mol

=19.15 Kg

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