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A basketball player can jump 1.6 m off the hardwood floor. With what upward velocity did he leave the floor?


1.4 m/s


2.8 m/s


4.2 m/s


5.6 m/s

Respuesta :

first do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2

= 31.36

Sq root = 5.6

Answer:

The upward velocity is 5.6 m/s.

(5) is correct option.

Explanation:

Given that,

Height = 1.6 m

We need to calculate the the upward velocity

Using equation of motion

[tex] v^2=u^2-2gh[/tex]

[tex]u=\sqrt{2gh}[/tex]

Here, g = acceleration due to gravity

v = final velocity

u = initial velocity

h = height

Put the value into the formula

[tex]u=\sqrt{2\times9.8\times1.6}[/tex]

[tex]u=5.6\ m/s[/tex]

Hence,  The upward velocity is 5.6 m/s.

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