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A person wishes to mix coffee worth ​$9 per lb with coffee worth ​$3 per lb to get 240 lb of a mixture worth ​$5 per lb. how many pounds of the ​$9 and the ​$3 coffees will be​ needed?

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82607618
Let x= lbs of the 9$ mix
      y= lbs of the 3$ mix
x+y=240
9x+3y=1200

Divide the second equation by -3 then combine to get -2x = -160.
Divide -160 by -2 to get the number of lbs of the $9 mix, 80lbs.
Subtract 80lbs from the lbs of the 5$ mix, 240lbs, to get the number of lbs of the $3 mix, 160lbs.

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