Answer: The solution of the system of the equation is, (8,-1)
Step-by-step explanation:
Using substitution method
[tex]2x+4y=12[/tex] .......... (1)
[tex]y=\frac{1}{4}x-3[/tex] ......... (2)
Now we are putting equation (2) into equation (1), we get the value of 'x'
[tex]2x+4(\frac{1}{4}x-3)=12[/tex]
[tex]2x+\frac{4}{4}x-4\times 3=12[/tex]
[tex]2x-x=12+12[/tex]
[tex]3x=24[/tex]
[tex]x=8[/tex]
Now put the value of 'x' in equation (2), we get the value of 'y'
[tex]y=\frac{1}{4}x-3[/tex]
[tex]y=\frac{1}{4}\times 8-3[/tex]
[tex]y=2-3[/tex]
[tex]y=-1[/tex]
Hence, the correct option is, (8,-1)
