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A liquid was analyzed to be 54.5% c, 9.10% h, and 36.4% o. an empty flask, whose mass was 45.32 g, when filled with the vapor of the liquid at 735mm hg and 99.2°c had a mass of 46.05 g. the volume of the flask was found to be 263.2 ml. type your answers using the format ch4 for ch4. enter the elements in the order given. what is the empirical formula of the compound? c2h4o correct: your answer is correct. what is the molecular formula of the compound?

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W0lf93
number Moles of C = 54.5 g / 12.011 = 4.54 number Moles of H = 9.10 / 1.008 = 9.02 number Moles of O = 36.4 / 16 = 2.28 if we want to divide by the smallest number 4.54 / 2.28 = 2 => C 9.02 / 2.28 = 4 => H 2.28 / 2.28 = 1 => O Empirical formula will be = C2H4O

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