Respuesta :
As restaurant owner
The probability of hiring Jun is 0.7 => p(J)
The probability of hiring Deron is 0.4 => p(D)
The probability of hiring at least one of you is 0.9 => p(J or D)
We have a probability equation:
p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D)
p(J and D) = 1.1 - 0.9 = 0.2
So the probability that both Jun and Deron get hired is 0.2.
The probability that both Jun and Deron get hired such that the probability that the owner hire Jun is 0.7, and the probability that owner hire Deron is 0.4 and the probability that owner hires at least one of them is 0.9 is [tex]0.2[/tex].
According to the question,
[tex]P(J)=0.7[/tex]
[tex]P(D)=0.4[/tex]
At least one of them hired [tex]P(J \cup D)=0.9[/tex]
[tex]P(J \cap D)=P(J)+P(D)-P(J\cup D)[/tex]
[tex]P(J \cap D)=0.7+0.4-0.9[/tex]
[tex]P(J \cap D)=1.1-0.9\\\\P(J \cap D)=0.2[/tex]
The probability that both Jun and Deron get hired is [tex]0.2[/tex].
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